What is (x+2)^2+(y-5)^2=3 ?

The solution to (x+2)^2+(y-5)^2=3 is Circle with (a,b)=(-2,5),r=sqrt(3)

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(x+2)^2+(y-5)^2=3

(x + 2)^{2} + (y - 5)^{2} = 3

(a, b) = (- 2, 5), r = 3

Solution steps

(x + 2)^{2} + (y - 5)^{2} = 3

Rewrite

(x + 2)^{2} + (y - 5)^{2} = 3

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 5)^{2} = (3)^{2}

Therefore the circle properties are:

(a, b) = (- 2, 5), r = 3

x^{2} + y^{2} + 6 x + 2 y - 6 = 0

x^{2} + y^{2} - 2 x - 4 y - 31 = 0

2 x^{2} + 2 y^{2} - 10 x + 6 y - 15 = 0

(x - 2)^{2} + (y + 6)^{2} = 16

x^{2} + y^{2} \geq 4

What is (x+2)^2+(y-5)^2=3 ?
The solution to (x+2)^2+(y-5)^2=3 is Circle with (a,b)=(-2,5),r=sqrt(3)