What is x^2+y^2-5x+3y-2=0 ?

The solution to x^2+y^2-5x+3y-2=0 is Circle with (a,b)=(5/2 ,-3/2),r=sqrt(21/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+y^2-5x+3y-2=0

x^{2} + y^{2} - 5 x + 3 y - 2 = 0

(a, b) = (\frac{5}{2}, - \frac{3}{2}), r = \frac{21}{2}

Solution steps

x^{2} + y^{2} - 5 x + 3 y - 2 = 0

Rewrite

x^{2} + y^{2} - 5 x + 3 y - 2 = 0

in the form of the standard circle equation

(x - \frac{5}{2})^{2} + (y - (- \frac{3}{2}))^{2} = (\frac{21}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{5}{2}, - \frac{3}{2}), r = \frac{21}{2}

(x + 11)^{2} + (y + 1)^{2} = 144

x^{2} + y^{2} + 10 x - 75 = 0

x^{2} - 6 x + y^{2} + 8 y - 24 = 0

(x - 4)^{2} + (y + 3)^{2} = 36

(x - 9)^{2} + (y + 4)^{2} = 25

What is x^2+y^2-5x+3y-2=0 ?
The solution to x^2+y^2-5x+3y-2=0 is Circle with (a,b)=(5/2 ,-3/2),r=sqrt(21/2)