What is (x+1)^2+(y-1)^2=1 ?

The solution to (x+1)^2+(y-1)^2=1 is Circle with (a,b)=(-1,1),r=1

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(x+1)^2+(y-1)^2=1

(x + 1)^{2} + (y - 1)^{2} = 1

(a, b) = (- 1, 1), r = 1

Solution steps

(x + 1)^{2} + (y - 1)^{2} = 1

Rewrite

(x + 1)^{2} + (y - 1)^{2} = 1

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 1)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (- 1, 1), r = 1

(x - 3)^{2} + (y - 1)^{2} = 9

x^{2} + y^{2} + 2 x - 8 y + 12 = 0

x^{2} + y^{2} - 2 x - 4 y - 8 = 0

9 x^{2} + 9 y^{2} + 42 x + 84 y = - 65

2 x^{2} + 2 y^{2} - 8 x - 12 y + 8 = 0

What is (x+1)^2+(y-1)^2=1 ?
The solution to (x+1)^2+(y-1)^2=1 is Circle with (a,b)=(-1,1),r=1