What is x^2+y^2-16x-8y=0 ?

The solution to x^2+y^2-16x-8y=0 is Circle with (a,b)=(8,4),r=4sqrt(5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+y^2-16x-8y=0

x^{2} + y^{2} - 16 x - 8 y = 0

(a, b) = (8, 4), r = 45

Solution steps

x^{2} + y^{2} - 16 x - 8 y = 0

Rewrite

x^{2} + y^{2} - 16 x - 8 y = 0

in the form of the standard circle equation

(x - 8)^{2} + (y - 4)^{2} = (45)^{2}

Therefore the circle properties are:

(a, b) = (8, 4), r = 45

(\frac{x - 7}{4})^{2} + (\frac{y + 3}{4})^{2} = \frac{169}{16}

x^{2} + y^{2} + 3 x + 4 y + 4 = 0

x^{2} + y^{2} - 10 x - 12 y + 45 = 0

(x - 4)^{2} + y^{2} = 16

x^{2} + y^{2} - 4 x - 12 y - 9 = 0

What is x^2+y^2-16x-8y=0 ?
The solution to x^2+y^2-16x-8y=0 is Circle with (a,b)=(8,4),r=4sqrt(5)