What is (x-2)^2+y^2=10 ?

The solution to (x-2)^2+y^2=10 is Circle with (a,b)=(2,0),r=sqrt(10)

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(x-2)^2+y^2=10

(x - 2)^{2} + y^{2} = 10

(a, b) = (2, 0), r = 10

Solution steps

(x - 2)^{2} + y^{2} = 10

Rewrite

(x - 2)^{2} + y^{2} = 10

in the form of the standard circle equation

(x - 2)^{2} + (y - 0)^{2} = (10)^{2}

Therefore the circle properties are:

(a, b) = (2, 0), r = 10

x^{2} + y^{2} - 6 x + 10 y - 15 = 0

(x + 1)^{2} + (y - 3)^{2} = 25

(x + 2)^{2} + (y - 5)^{2} = 4

x^{2} + y^{2} = 53

x^{2} + y^{2} = 6 x

What is (x-2)^2+y^2=10 ?
The solution to (x-2)^2+y^2=10 is Circle with (a,b)=(2,0),r=sqrt(10)