What is (x+6)^2+(y+2)^2=40 ?

The solution to (x+6)^2+(y+2)^2=40 is Circle with (a,b)=(-6,-2),r=sqrt(40)

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(x+6)^2+(y+2)^2=40

(x + 6)^{2} + (y + 2)^{2} = 40

(a, b) = (- 6, - 2), r = 40

Solution steps

(x + 6)^{2} + (y + 2)^{2} = 40

Rewrite

(x + 6)^{2} + (y + 2)^{2} = 40

in the form of the standard circle equation

(x - (- 6))^{2} + (y - (- 2))^{2} = (40)^{2}

Therefore the circle properties are:

(a, b) = (- 6, - 2), r = 40

x^{2} + y^{2} = 289

x^{2} + y^{2} - 12 x - 8 y + 3 = 0

x^{2} + y^{2} - 6 x - 4 y - 23 = 0

x^{2} + y^{2} = 2.5

x^{2} + y^{2} + 6 x - 4 y = 387

What is (x+6)^2+(y+2)^2=40 ?
The solution to (x+6)^2+(y+2)^2=40 is Circle with (a,b)=(-6,-2),r=sqrt(40)