What is x^2+(y-4)^2= 25/9 ?

The solution to x^2+(y-4)^2= 25/9 is Circle with (a,b)=(0,4),r= 5/3

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x^2+(y-4)^2= 25/9

x^{2} + (y - 4)^{2} = \frac{25}{9}

(a, b) = (0, 4), r = \frac{5}{3}

Solution steps

x^{2} + (y - 4)^{2} = \frac{25}{9}

Rewrite

x^{2} + (y - 4)^{2} = \frac{25}{9}

in the form of the standard circle equation

(x - 0)^{2} + (y - 4)^{2} = (\frac{5}{3})^{2}

Therefore the circle properties are:

(a, b) = (0, 4), r = \frac{5}{3}

x^{2} + y^{2} = \frac{9}{4}

x^{2} + y^{2} + 12 x - 2 y = - 1

(x - 0)^{2} + (y - 0)^{2} = 5^{2}

(x - 7)^{2} + (y - 3)^{2} = 9

x^{2} + y^{2} - 50 = 0

What is x^2+(y-4)^2= 25/9 ?
The solution to x^2+(y-4)^2= 25/9 is Circle with (a,b)=(0,4),r= 5/3