What is (x-2)^2+(y+5)^2=16 ?

The solution to (x-2)^2+(y+5)^2=16 is Circle with (a,b)=(2,-5),r=4

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(x-2)^2+(y+5)^2=16

(x - 2)^{2} + (y + 5)^{2} = 16

(a, b) = (2, - 5), r = 4

Solution steps

(x - 2)^{2} + (y + 5)^{2} = 16

Rewrite

(x - 2)^{2} + (y + 5)^{2} = 16

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 5))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (2, - 5), r = 4

x^{2} + (y + 5)^{2} = 25

(x - 3)^{2} + y^{2} = \frac{1}{9}

(x + 2)^{2} + y^{2} = 36

x^{2} + (y - 3960)^{2} = 396 0^{2}

a^{2} + b^{2} = 9

What is (x-2)^2+(y+5)^2=16 ?
The solution to (x-2)^2+(y+5)^2=16 is Circle with (a,b)=(2,-5),r=4