What is (x-3)^{(2)}+(y+2)^{(2)}=49 ?

The solution to (x-3)^{(2)}+(y+2)^{(2)}=49 is Circle with (a,b)=(3,-2),r=7

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(x-3)^{(2)}+(y+2)^{(2)}=49

(x - 3)^{(2)} + (y + 2)^{(2)} = 49

(a, b) = (3, - 2), r = 7

Solution steps

(x - 3)^{2} + (y + 2)^{2} = 49

Rewrite

(x - 3)^{2} + (y + 2)^{2} = 49

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 2))^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (3, - 2), r = 7

(x - \frac{3}{2})^{2} + (y - \frac{3}{2})^{2} = \frac{9}{4}

x^{2} - 6 x + y^{2} - 8 y = 39

x^{2} + (y + 2)^{2} = 49

X^{2} + Y^{2} = 4

(x - 1)^{2} + (y + 2)^{2} = 49

What is (x-3)^{(2)}+(y+2)^{(2)}=49 ?
The solution to (x-3)^{(2)}+(y+2)^{(2)}=49 is Circle with (a,b)=(3,-2),r=7