What is (x+3)^2+(y+1)^2=25 ?

The solution to (x+3)^2+(y+1)^2=25 is Circle with (a,b)=(-3,-1),r=5

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(x+3)^2+(y+1)^2=25

(x + 3)^{2} + (y + 1)^{2} = 25

(a, b) = (- 3, - 1), r = 5

Solution steps

(x + 3)^{2} + (y + 1)^{2} = 25

Rewrite

(x + 3)^{2} + (y + 1)^{2} = 25

in the form of the standard circle equation

(x - (- 3))^{2} + (y - (- 1))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 3, - 1), r = 5

(x - 3)^{2} + (y + 7)^{2} = 16

(x - \frac{5}{2})^{2} + (y - \frac{1}{2})^{2} = \frac{169}{4}

(x - 13)^{2} + (y + 13)^{2} = 16

x^{2} + 6 x + y^{2} - 2 y + 3 = 0

x^{2} + y^{2} - 18 x + 16 y + 120 = 0

What is (x+3)^2+(y+1)^2=25 ?
The solution to (x+3)^2+(y+1)^2=25 is Circle with (a,b)=(-3,-1),r=5