What is 8x+32y+y^2=-263-x^2 ?

The solution to 8x+32y+y^2=-263-x^2 is Circle with (a,b)=(-4,-16),r=3

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8x+32y+y^2=-263-x^2

8 x + 32 y + y^{2} = - 263 - x^{2}

(a, b) = (- 4, - 16), r = 3

Solution steps

8 x + 32 y + y^{2} = - 263 - x^{2}

Rewrite

8 x + 32 y + y^{2} = - 263 - x^{2}

in the form of the standard circle equation

(x - (- 4))^{2} + (y - (- 16))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 4, - 16), r = 3

2 x^{2} + 2 y^{2} - 8 x + 28 y + 86 = 0

(x + 12)^{2} + (Y (x) - 4)^{2} - 30 = 0

x^{2} - 6 x + y^{2} + 2 y + 6 = 0

x^{2} + y^{2} - x + 6 y + 9 = 0

x^{2} + y^{2} + 24 x + 10 y + 160 = 0

What is 8x+32y+y^2=-263-x^2 ?
The solution to 8x+32y+y^2=-263-x^2 is Circle with (a,b)=(-4,-16),r=3