What is 9x^2+9y^2-12x+36y-104=0 ?

The solution to 9x^2+9y^2-12x+36y-104=0 is Circle with (a,b)=(2/3 ,-2),r=4

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9x^2+9y^2-12x+36y-104=0

9 x^{2} + 9 y^{2} - 12 x + 36 y - 104 = 0

(a, b) = (\frac{2}{3}, - 2), r = 4

Solution steps

9 x^{2} + 9 y^{2} - 12 x + 36 y - 104 = 0

Rewrite

9 x^{2} + 9 y^{2} - 12 x + 36 y - 104 = 0

in the form of the standard circle equation

(x - \frac{2}{3})^{2} + (y - (- 2))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (\frac{2}{3}, - 2), r = 4

x^{2} + 4 x + y^{2} - 4 y = 1

2 x^{2} + 2 y^{2} + x + y = 0

(x + 3)^{2} + (y - 2)^{2} = 1

9 x^{2} + 9 y^{2} = 16

x^{2} + y^{2} + 4 y - 117 = 0

What is 9x^2+9y^2-12x+36y-104=0 ?
The solution to 9x^2+9y^2-12x+36y-104=0 is Circle with (a,b)=(2/3 ,-2),r=4