What is (x-4)^2+(y-4)^2=7 ?

The solution to (x-4)^2+(y-4)^2=7 is Circle with (a,b)=(4,4),r=sqrt(7)

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(x-4)^2+(y-4)^2=7

(x - 4)^{2} + (y - 4)^{2} = 7

(a, b) = (4, 4), r = 7

Solution steps

(x - 4)^{2} + (y - 4)^{2} = 7

Rewrite

(x - 4)^{2} + (y - 4)^{2} = 7

in the form of the standard circle equation

(x - 4)^{2} + (y - 4)^{2} = (7)^{2}

Therefore the circle properties are:

(a, b) = (4, 4), r = 7

(x + 6)^{2} + y^{2} = 9

x^{2} + y^{2} - 6 x - 2 y + 6 = 0

x^{2} + y^{2} = 425

x^{2} + y^{2} = 400

(x + 1)^{2} + (y + 2)^{2} = 8

What is (x-4)^2+(y-4)^2=7 ?
The solution to (x-4)^2+(y-4)^2=7 is Circle with (a,b)=(4,4),r=sqrt(7)