What is (x-5)^2+(y+7)^2=50 ?

The solution to (x-5)^2+(y+7)^2=50 is Circle with (a,b)=(5,-7),r=sqrt(50)

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(x-5)^2+(y+7)^2=50

(x - 5)^{2} + (y + 7)^{2} = 50

(a, b) = (5, - 7), r = 50

Solution steps

(x - 5)^{2} + (y + 7)^{2} = 50

Rewrite

(x - 5)^{2} + (y + 7)^{2} = 50

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 7))^{2} = (50)^{2}

Therefore the circle properties are:

(a, b) = (5, - 7), r = 50

x^{2} + (y + 8)^{2} = 36

(x + 3)^{2} + (y - 4)^{2} = 4

x^{2} + y^{2} - 10 x + 14 y + 25 = 0

5 x^{2} + 5 y^{2} + 30 x - 20 y + 20 = 0

x^{2} = 36 - y^{2}

What is (x-5)^2+(y+7)^2=50 ?
The solution to (x-5)^2+(y+7)^2=50 is Circle with (a,b)=(5,-7),r=sqrt(50)