What is x^2-10x+y^2+8=0 ?

The solution to x^2-10x+y^2+8=0 is Circle with (a,b)=(5,0),r=sqrt(17)

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x^2-10x+y^2+8=0

x^{2} - 10 x + y^{2} + 8 = 0

(a, b) = (5, 0), r = 17

Solution steps

x^{2} - 10 x + y^{2} + 8 = 0

Rewrite

x^{2} - 10 x + y^{2} + 8 = 0

in the form of the standard circle equation

(x - 5)^{2} + (y - 0)^{2} = (17)^{2}

Therefore the circle properties are:

(a, b) = (5, 0), r = 17

x^{2} + y^{2} - 4 x + 18 y + 35 = 0

- 4 y^{2} - 4 x^{2} - 20 x + 32 y + 81 = 0

4 (x - 3)^{2} + 4 y^{2} = 4

x^{2} + y^{2} + 2 x - 14 y = - 25

x^{2} + y^{2} + 4 x - 6 y - 16 = 0

What is x^2-10x+y^2+8=0 ?
The solution to x^2-10x+y^2+8=0 is Circle with (a,b)=(5,0),r=sqrt(17)