What is 9x^2+25y^2-36x-50y+60=0 ?

The solution to 9x^2+25y^2-36x-50y+60=0 is Ellipse with (h,k)=(2,1),a= 1/3 ,b= 1/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9x^2+25y^2-36x-50y+60=0

9 x^{2} + 25 y^{2} - 36 x - 50 y + 60 = 0

(h, k) = (2, 1), a = \frac{1}{3}, b = \frac{1}{5}

Solution steps

9 x^{2} + 25 y^{2} - 36 x - 50 y + 60 = 0

Rewrite

9 x^{2} + 25 y^{2} - 36 x - 50 y + 60 = 0

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{( \frac{1}{3} ) ^{2}} + \frac{( y - 1 ) ^{2}}{( \frac{1}{5} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, 1), a = \frac{1}{3}, b = \frac{1}{5}

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (2, 1), a = \frac{1}{3}, b = \frac{1}{5}

x^{2} - \frac{y ^{2}}{4} = 1

25 x^{2} - 10 x - 200 y - 119 = 0

\frac{x ^{2}}{16} - \frac{y ^{2}}{4} = 1

y^{2} = 8 x

y^{2} = - 8 x

What is 9x^2+25y^2-36x-50y+60=0 ?
The solution to 9x^2+25y^2-36x-50y+60=0 is Ellipse with (h,k)=(2,1),a= 1/3 ,b= 1/5