What is x^2+y^2-2x+2y-2=0 ?

The solution to x^2+y^2-2x+2y-2=0 is Circle with (a,b)=(1,-1),r=2

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x^2+y^2-2x+2y-2=0

x^{2} + y^{2} - 2 x + 2 y - 2 = 0

(a, b) = (1, - 1), r = 2

Solution steps

x^{2} + y^{2} - 2 x + 2 y - 2 = 0

Rewrite

x^{2} + y^{2} - 2 x + 2 y - 2 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 1))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (1, - 1), r = 2

x^{2} + y^{2} = 45

x^{2} + y^{2} = 41

x^{2} + y^{2} = 56

(x - 1)^{2} + (y - 2)^{2} = 36

x^{2} + y^{2} = 24

What is x^2+y^2-2x+2y-2=0 ?
The solution to x^2+y^2-2x+2y-2=0 is Circle with (a,b)=(1,-1),r=2