What is 3x^2+3y^2-6x+9y+5=0 ?

The solution to 3x^2+3y^2-6x+9y+5=0 is Circle with (a,b)=(1,-3/2),r=(sqrt(19))/(2sqrt(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3x^2+3y^2-6x+9y+5=0

3 x^{2} + 3 y^{2} - 6 x + 9 y + 5 = 0

(a, b) = (1, - \frac{3}{2}), r = \frac{19}{2 3}

Solution steps

3 x^{2} + 3 y^{2} - 6 x + 9 y + 5 = 0

Rewrite

3 x^{2} + 3 y^{2} - 6 x + 9 y + 5 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - (- \frac{3}{2}))^{2} = (\frac{19}{2 3})^{2}

Therefore the circle properties are:

(a, b) = (1, - \frac{3}{2}), r = \frac{19}{2 3}

2 x^{2} + 12 x + 18 - y^{2} = 3 (2 - y^{2}) + 4 y

x^{2} + y^{2} - x \geq 0

x^{2} + y^{2} = 196

2 x^{2} + 2 y^{2} - 16 x + 4 y + 20 = 0

(x + \frac{1}{2})^{2} + (y - 2)^{2} = 3

What is 3x^2+3y^2-6x+9y+5=0 ?
The solution to 3x^2+3y^2-6x+9y+5=0 is Circle with (a,b)=(1,-3/2),r=(sqrt(19))/(2sqrt(3))