What is (x+3)^2+(y-7)^2=9 ?

The solution to (x+3)^2+(y-7)^2=9 is Circle with (a,b)=(-3,7),r=3

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(x+3)^2+(y-7)^2=9

(x + 3)^{2} + (y - 7)^{2} = 9

(a, b) = (- 3, 7), r = 3

Solution steps

(x + 3)^{2} + (y - 7)^{2} = 9

Rewrite

(x + 3)^{2} + (y - 7)^{2} = 9

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 7)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 3, 7), r = 3

(x - 3)^{2} + 2 y + 1 - 81 = - y^{2}

(x + 4)^{2} + (y + 2)^{2} = 16

x^{2} + y^{2} - 4 x - 2 y = 11

x^{2} + y^{2} - 2 x - 2 y = 0

x^{2} + 2 x + y^{2} = 3

What is (x+3)^2+(y-7)^2=9 ?
The solution to (x+3)^2+(y-7)^2=9 is Circle with (a,b)=(-3,7),r=3