What is (x-2)^2+(y-2)^2=16 ?

The solution to (x-2)^2+(y-2)^2=16 is Circle with (a,b)=(2,2),r=4

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(x-2)^2+(y-2)^2=16

(x - 2)^{2} + (y - 2)^{2} = 16

(a, b) = (2, 2), r = 4

Solution steps

(x - 2)^{2} + (y - 2)^{2} = 16

Rewrite

(x - 2)^{2} + (y - 2)^{2} = 16

in the form of the standard circle equation

(x - 2)^{2} + (y - 2)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (2, 2), r = 4

x^{2} + y^{2} - 4 x + 6 y = 3

\frac{x ^{2} + y ^{2}}{4} = 1

x^{2} + y^{2} - 2 x - 4 y - 11 = 0

x^{2} + y^{2} - 12 x + 16 y + 36 = 0

y^{2} + x^{2} - 4 x + 10 y + 13 = 0

What is (x-2)^2+(y-2)^2=16 ?
The solution to (x-2)^2+(y-2)^2=16 is Circle with (a,b)=(2,2),r=4