What is (x-2)^2+(y-3)^2=10 ?

The solution to (x-2)^2+(y-3)^2=10 is Circle with (a,b)=(2,3),r=sqrt(10)

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(x-2)^2+(y-3)^2=10

(x - 2)^{2} + (y - 3)^{2} = 10

(a, b) = (2, 3), r = 10

Solution steps

(x - 2)^{2} + (y - 3)^{2} = 10

Rewrite

(x - 2)^{2} + (y - 3)^{2} = 10

in the form of the standard circle equation

(x - 2)^{2} + (y - 3)^{2} = (10)^{2}

Therefore the circle properties are:

(a, b) = (2, 3), r = 10

9 x^{2} + 9 y^{2} = 64

(x - 2)^{2} + (y - 3)^{2} = 49

4 x^{2} + 4 y^{2} + 16 x - 12 y + 1 = 0

x^{2} + y^{2} + 84 x - 22 y + 861 = 0

x^{2} + y^{2} + 6 x - 6 y + 9 = 0

What is (x-2)^2+(y-3)^2=10 ?
The solution to (x-2)^2+(y-3)^2=10 is Circle with (a,b)=(2,3),r=sqrt(10)