What is (x-4)^2+y^2=1 ?

The solution to (x-4)^2+y^2=1 is Circle with (a,b)=(4,0),r=1

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(x-4)^2+y^2=1

(x - 4)^{2} + y^{2} = 1

(a, b) = (4, 0), r = 1

Solution steps

(x - 4)^{2} + y^{2} = 1

Rewrite

(x - 4)^{2} + y^{2} = 1

in the form of the standard circle equation

(x - 4)^{2} + (y - 0)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (4, 0), r = 1

(x + 2)^{2} + (y + 5)^{2} = 100

x^{2} + y^{2} - 16 x + 8 y + 71 = 0

x^{2} - 2 x + y^{2} = 0

9 x^{2} + 9 y^{2} - 6 x - 36 y - 107 = 0

(x - 5)^{2} + (y - 1)^{2} = 25

What is (x-4)^2+y^2=1 ?
The solution to (x-4)^2+y^2=1 is Circle with (a,b)=(4,0),r=1