What is x^2+y^2+10y+11=0 ?

The solution to x^2+y^2+10y+11=0 is Circle with (a,b)=(0,-5),r=sqrt(14)

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x^2+y^2+10y+11=0

x^{2} + y^{2} + 10 y + 11 = 0

(a, b) = (0, - 5), r = 14

Solution steps

x^{2} + y^{2} + 10 y + 11 = 0

Rewrite

x^{2} + y^{2} + 10 y + 11 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 5))^{2} = (14)^{2}

Therefore the circle properties are:

(a, b) = (0, - 5), r = 14

x^{2} + y^{2} + 10 x - 8 y - 6 = 0

2 x^{2} + 2 y^{2} - 4 x + 12 y - 12 = 0

x^{2} + y^{2} - 8 x - 4 y + 4 = 0

4 x^{2} + 4 y^{2} - 16 x + 20 y + 25 = 0

x^{2} + y^{2} + 8 x - 6 y = - 18

What is x^2+y^2+10y+11=0 ?
The solution to x^2+y^2+10y+11=0 is Circle with (a,b)=(0,-5),r=sqrt(14)