What is (x^2-4x)+(y^2-6y)=-9 ?

The solution to (x^2-4x)+(y^2-6y)=-9 is Circle with (a,b)=(2,3),r=2

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(x^2-4x)+(y^2-6y)=-9

(x^{2} - 4 x) + (y^{2} - 6 y) = - 9

(a, b) = (2, 3), r = 2

Solution steps

x^{2} - 4 x + (y^{2} - 6 y) = - 9

Rewrite

x^{2} - 4 x + (y^{2} - 6 y) = - 9

in the form of the standard circle equation

(x - 2)^{2} + (y - 3)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (2, 3), r = 2

2 x^{2} + 2 y^{2} - 2 x + 2 y - 1 = 0

2 x^{2} + 2 y^{2} + 4 x + 12 y - 2 = 0

(x - 12)^{2} + (y - 4)^{2} = 4

x^{2} + y^{2} + 12 x - 6 y + 36 = 0

(x - 8)^{2} + (y - 1)^{2} = 1

What is (x^2-4x)+(y^2-6y)=-9 ?
The solution to (x^2-4x)+(y^2-6y)=-9 is Circle with (a,b)=(2,3),r=2