What is p^2+q^2=170 ?

The solution to p^2+q^2=170 is Circle with (a,b)=(0,0),r=sqrt(170)

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p^2+q^2=170

p^{2} + q^{2} = 170

(a, b) = (0, 0), r = 170

Solution steps

p^{2} + q^{2} = 170

Rewrite

p^{2} + q^{2} = 170

in the form of the standard circle equation

(p - 0)^{2} + (q - 0)^{2} = (170)^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 170

x^{2} + y^{2} - 8 x - 2 y + 11 = 0

(x + 4)^{2} + (y - 1)^{2} = 8

x^{2} + y^{2} - 12 x + 8 y - 60 = 0

x^{2} + y^{2} + 2 x = 3

x^{2} + (y + 3)^{2} = 25

What is p^2+q^2=170 ?
The solution to p^2+q^2=170 is Circle with (a,b)=(0,0),r=sqrt(170)