What is x^2+y^2+8x-12y-8=0 ?

The solution to x^2+y^2+8x-12y-8=0 is Circle with (a,b)=(-4,6),r=2sqrt(15)

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x^2+y^2+8x-12y-8=0

x^{2} + y^{2} + 8 x - 12 y - 8 = 0

(a, b) = (- 4, 6), r = 215

Solution steps

x^{2} + y^{2} + 8 x - 12 y - 8 = 0

Rewrite

x^{2} + y^{2} + 8 x - 12 y - 8 = 0

in the form of the standard circle equation

(x - (- 4))^{2} + (y - 6)^{2} = (215)^{2}

Therefore the circle properties are:

(a, b) = (- 4, 6), r = 215

(x - 2)^{2} + (y + 2)^{2} = 16

x^{2} + y^{2} + 4 x + 4 y - 1 = 0

x^{2} + y^{2} - 13 = 0

x^{2} + (y + 1)^{2} = 1

10 (x + 5)^{2} + 10 (y - 8)^{2} = 1000

What is x^2+y^2+8x-12y-8=0 ?
The solution to x^2+y^2+8x-12y-8=0 is Circle with (a,b)=(-4,6),r=2sqrt(15)