What is 4x^2+4y^2=9 ?

The solution to 4x^2+4y^2=9 is Circle with (a,b)=(0,0),r= 3/2

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4x^2+4y^2=9

4 x^{2} + 4 y^{2} = 9

(a, b) = (0, 0), r = \frac{3}{2}

Solution steps

4 x^{2} + 4 y^{2} = 9

Rewrite

4 x^{2} + 4 y^{2} = 9

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (\frac{3}{2})^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = \frac{3}{2}

x^{2} + y^{2} - 16 x + 4 y + 64 = 0

(x - 2)^{2} + (y + 3)^{2} = 1

3 x^{2} + 3 y^{2} - 12 x + 18 y - 9 = 0

x^{2} + y^{2} - 4 x + 6 y = - 1

(x + 5)^{2} + (y + 2)^{2} = 9

What is 4x^2+4y^2=9 ?
The solution to 4x^2+4y^2=9 is Circle with (a,b)=(0,0),r= 3/2