What is 6x^2+6y^2+12x-y=0 ?

The solution to 6x^2+6y^2+12x-y=0 is Circle with (a,b)=(-1, 1/12),r=(sqrt(145))/(12)

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6x^2+6y^2+12x-y=0

6 x^{2} + 6 y^{2} + 12 x - y = 0

(a, b) = (- 1, \frac{1}{12}), r = \frac{145}{12}

Solution steps

6 x^{2} + 6 y^{2} + 12 x - y = 0

Rewrite

6 x^{2} + 6 y^{2} + 12 x - y = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - \frac{1}{12})^{2} = (\frac{145}{12})^{2}

Therefore the circle properties are:

(a, b) = (- 1, \frac{1}{12}), r = \frac{145}{12}

(x - 3)^{2} + (y + 1)^{2} = 36

x^{2} + y^{2} - 4 x + 3 y - 8 = 0

3 x^{2} + 3 y^{2} - 12 x + 18 y + 3 = 0

(x + 4)^{2} + (y - \frac{3}{4})^{2} = 125

(x + 6)^{2} + (y - 1)^{2} = 16

What is 6x^2+6y^2+12x-y=0 ?
The solution to 6x^2+6y^2+12x-y=0 is Circle with (a,b)=(-1, 1/12),r=(sqrt(145))/(12)