What is x^2+y^2+9x=0 ?

The solution to x^2+y^2+9x=0 is Circle with (a,b)=(-9/2 ,0),r= 9/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+y^2+9x=0

x^{2} + y^{2} + 9 x = 0

(a, b) = (- \frac{9}{2}, 0), r = \frac{9}{2}

Solution steps

x^{2} + y^{2} + 9 x = 0

Rewrite

x^{2} + y^{2} + 9 x = 0

in the form of the standard circle equation

(x - (- \frac{9}{2}))^{2} + (y - 0)^{2} = (\frac{9}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{9}{2}, 0), r = \frac{9}{2}

x^{2} - 10 x = - y^{2} + 16 y - 40

x^{2} + y^{2} + 8 x + 2 y + 8 = 0

x^{2} + 12 x + y^{2} - 6 y - 36 = 0

(x - 2)^{2} + (y - 1)^{2} = 3

a^{2} + b^{2} = 8^{2}

What is x^2+y^2+9x=0 ?
The solution to x^2+y^2+9x=0 is Circle with (a,b)=(-9/2 ,0),r= 9/2