What is 2x^{(2)}+2y^{(2)}+10x=2y+7 ?

The solution to 2x^{(2)}+2y^{(2)}+10x=2y+7 is Circle with (a,b)=(-5/2 , 1/2),r=sqrt(10)

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2x^{(2)}+2y^{(2)}+10x=2y+7

2 x^{(2)} + 2 y^{(2)} + 10 x = 2 y + 7

(a, b) = (- \frac{5}{2}, \frac{1}{2}), r = 10

Solution steps

2 x^{2} + 2 y^{2} + 10 x = 2 y + 7

Rewrite

2 x^{2} + 2 y^{2} + 10 x = 2 y + 7

in the form of the standard circle equation

(x - (- \frac{5}{2}))^{2} + (y - \frac{1}{2})^{2} = (10)^{2}

Therefore the circle properties are:

(a, b) = (- \frac{5}{2}, \frac{1}{2}), r = 10

(x + 2)^{2} + (y + 5)^{2} = 16

2 x^{2} + 2 y^{2} + 8 x - 4 y - 22 = 0

x^{2} + y^{2} - 2 x + y = 0

x^{2} + y^{2} + 5 x - 3 y - 8 = 0

(x + 4)^{2} + (y - 2)^{2} = 9

What is 2x^{(2)}+2y^{(2)}+10x=2y+7 ?
The solution to 2x^{(2)}+2y^{(2)}+10x=2y+7 is Circle with (a,b)=(-5/2 , 1/2),r=sqrt(10)