What is -2y^2+x-20y-49=0 ?

The solution to -2y^2+x-20y-49=0 is Parabola with (h,k)=(-1,-5),p= 1/8

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-2y^2+x-20y-49=0

- 2 y^{2} + x - 20 y - 49 = 0

(h, k) = (- 1, - 5), p = \frac{1}{8}

Solution steps

- 2 y^{2} + x - 20 y - 49 = 0

Rewrite

- 2 y^{2} + x - 20 y - 49 = 0

in the standard form

4 \cdot \frac{1}{8} (x - (- 1)) = (y - (- 5))^{2}

Therefore parabola properties are:

(h, k) = (- 1, - 5), p = \frac{1}{8}

x + y^{2} = 3

x - y^{2} = 1

y \geq x^{2} - 1

y^{2} - 2 y - 12 x + 25 = 0

36 y^{2} + 72 x - 132 y - 239 = 0

What is -2y^2+x-20y-49=0 ?
The solution to -2y^2+x-20y-49=0 is Parabola with (h,k)=(-1,-5),p= 1/8