What is (x-3/2)^2+(y-7)^2=5^2 ?

The solution to (x-3/2)^2+(y-7)^2=5^2 is Circle with (a,b)=(3/2 ,7),r=5

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(x-3/2)^2+(y-7)^2=5^2

(x - \frac{3}{2})^{2} + (y - 7)^{2} = 5^{2}

(a, b) = (\frac{3}{2}, 7), r = 5

Solution steps

(x - \frac{3}{2})^{2} + (y - 7)^{2} = 5^{2}

Rewrite

(x - \frac{3}{2})^{2} + (y - 7)^{2} = 5^{2}

in the form of the standard circle equation

(x - \frac{3}{2})^{2} + (y - 7)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (\frac{3}{2}, 7), r = 5

(x - 3.5)^{2} + (y - 3)^{2} < 4.1

x^{2} + (y + 14)^{2} = 25

x^{2} + y^{2} - 12 x + 12 y + 36 = 0

(x - 7)^{2} + (y + 2)^{2} = 16

x^{2} + y^{2} - 2 x + 8 y + 13 = 0

What is (x-3/2)^2+(y-7)^2=5^2 ?
The solution to (x-3/2)^2+(y-7)^2=5^2 is Circle with (a,b)=(3/2 ,7),r=5