What is (x+8)^2+(y+5)^2=256 ?

The solution to (x+8)^2+(y+5)^2=256 is Circle with (a,b)=(-8,-5),r=16

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(x+8)^2+(y+5)^2=256

(x + 8)^{2} + (y + 5)^{2} = 256

(a, b) = (- 8, - 5), r = 16

Solution steps

(x + 8)^{2} + (y + 5)^{2} = 256

Rewrite

(x + 8)^{2} + (y + 5)^{2} = 256

in the form of the standard circle equation

(x - (- 8))^{2} + (y - (- 5))^{2} = 1 6^{2}

Therefore the circle properties are:

(a, b) = (- 8, - 5), r = 16

x^{2} - 16 x + y^{2} - 36 = 0

(x - \frac{7}{4})^{2} + (y - \frac{3}{4})^{2} = \frac{169}{16}

x^{2} + y^{2} + 6 x - 22 y + 120 = 0

(x + 4)^{2} + (y + 5)^{2} = 36

(x - 6)^{2} + (y - 7)^{2} = 8^{2}

What is (x+8)^2+(y+5)^2=256 ?
The solution to (x+8)^2+(y+5)^2=256 is Circle with (a,b)=(-8,-5),r=16