What is x^2+y^2+10x=11-2y ?

The solution to x^2+y^2+10x=11-2y is Circle with (a,b)=(-5,-1),r=sqrt(37)

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x^2+y^2+10x=11-2y

x^{2} + y^{2} + 10 x = 11 - 2 y

(a, b) = (- 5, - 1), r = 37

Solution steps

x^{2} + y^{2} + 10 x = 11 - 2 y

Rewrite

x^{2} + y^{2} + 10 x = 11 - 2 y

in the form of the standard circle equation

(x - (- 5))^{2} + (y - (- 1))^{2} = (37)^{2}

Therefore the circle properties are:

(a, b) = (- 5, - 1), r = 37

x^{2} + (y - 5)^{2} = 81

2 x^{2} - 8 x + 2 y^{2} + 12 y + 14 = 0

(y - 2)^{2} = 4 - x^{2}

(x - 0)^{2} + (y - 0)^{2} = 2^{2}

x^{2} = 25 - y^{2}

What is x^2+y^2+10x=11-2y ?
The solution to x^2+y^2+10x=11-2y is Circle with (a,b)=(-5,-1),r=sqrt(37)