What is (x-6)^2+(y+2)^2=25 ?

The solution to (x-6)^2+(y+2)^2=25 is Circle with (a,b)=(6,-2),r=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-6)^2+(y+2)^2=25

(x - 6)^{2} + (y + 2)^{2} = 25

(a, b) = (6, - 2), r = 5

Solution steps

(x - 6)^{2} + (y + 2)^{2} = 25

Rewrite

(x - 6)^{2} + (y + 2)^{2} = 25

in the form of the standard circle equation

(x - 6)^{2} + (y - (- 2))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (6, - 2), r = 5

2 x^{2} - 20 x + 2 y^{2} + 12 y = - 18

(x - 5)^{2} + y^{2} - 8 y = 0

x^{2} + y^{2} - 8 x + 4 y = 0

(x + 4)^{2} + (y - 4 \frac{1}{2})^{2} = 42 \frac{1}{4}

x^{2} + y^{2} + 8 x - 2 y + 13 = 0

What is (x-6)^2+(y+2)^2=25 ?
The solution to (x-6)^2+(y+2)^2=25 is Circle with (a,b)=(6,-2),r=5