What is (x+3)^2+(y-3)^2=8 ?

The solution to (x+3)^2+(y-3)^2=8 is Circle with (a,b)=(-3,3),r=sqrt(8)

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(x+3)^2+(y-3)^2=8

(x + 3)^{2} + (y - 3)^{2} = 8

(a, b) = (- 3, 3), r = 8

Solution steps

(x + 3)^{2} + (y - 3)^{2} = 8

Rewrite

(x + 3)^{2} + (y - 3)^{2} = 8

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 3)^{2} = (8)^{2}

Therefore the circle properties are:

(a, b) = (- 3, 3), r = 8

(x^{2} + y^{2}) = 58

9 x^{2} + 6 x + 8 + 9 y^{2} - 24 y = 0

x^{2} + (y - 6)^{2} = 16

(x + 4)^{2} + (y - 4)^{2} = 16

x^{(2)} + y^{(2)} - 6 x + 2 y = - 1

What is (x+3)^2+(y-3)^2=8 ?
The solution to (x+3)^2+(y-3)^2=8 is Circle with (a,b)=(-3,3),r=sqrt(8)