What is x^2-2x+y^2+6y+6=0 ?

The solution to x^2-2x+y^2+6y+6=0 is Circle with (a,b)=(1,-3),r=2

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x^2-2x+y^2+6y+6=0

x^{2} - 2 x + y^{2} + 6 y + 6 = 0

(a, b) = (1, - 3), r = 2

Solution steps

x^{2} - 2 x + y^{2} + 6 y + 6 = 0

Rewrite

x^{2} - 2 x + y^{2} + 6 y + 6 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 3))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (1, - 3), r = 2

2 x^{2} + 2 y^{2} + 44 x + 28 y = 52

x^{2} + (y - 8)^{2} = 5

(x - 6)^{2} + (y - 4)^{2} = 5^{2}

25.314 4^{2} = (27.2 - x)^{2} + (27.2 - y)^{2}

x^{2} - 4 x + y^{2} + 6 y + 4 = 0

What is x^2-2x+y^2+6y+6=0 ?
The solution to x^2-2x+y^2+6y+6=0 is Circle with (a,b)=(1,-3),r=2