What is (x-4)^2+(y+3)^2=25 ?

The solution to (x-4)^2+(y+3)^2=25 is Circle with (a,b)=(4,-3),r=5

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(x-4)^2+(y+3)^2=25

(x - 4)^{2} + (y + 3)^{2} = 25

(a, b) = (4, - 3), r = 5

Solution steps

(x - 4)^{2} + (y + 3)^{2} = 25

Rewrite

(x - 4)^{2} + (y + 3)^{2} = 25

in the form of the standard circle equation

(x - 4)^{2} + (y - (- 3))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (4, - 3), r = 5

x^{2} + y^{2} - 6 x - 16 y + 24 = 0

x^{(2)} + y^{(2)} - 4 x - 6 y + 9 = 0

(x - 4)^{2} + (y + 3)^{2} = 16

x^{2} = 5 - y^{2}

y^{2} = - x^{2} + 5 x - 6

What is (x-4)^2+(y+3)^2=25 ?
The solution to (x-4)^2+(y+3)^2=25 is Circle with (a,b)=(4,-3),r=5