What is (x-4)^2+(y-2)^2=4 ?

The solution to (x-4)^2+(y-2)^2=4 is Circle with (a,b)=(4,2),r=2

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(x-4)^2+(y-2)^2=4

(x - 4)^{2} + (y - 2)^{2} = 4

(a, b) = (4, 2), r = 2

Solution steps

(x - 4)^{2} + (y - 2)^{2} = 4

Rewrite

(x - 4)^{2} + (y - 2)^{2} = 4

in the form of the standard circle equation

(x - 4)^{2} + (y - 2)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (4, 2), r = 2

x - y + x^{2} + y^{2} - 1 = 0

x^{2} + y^{2} = 4^{2}

x, p (x)^{2} + x^{2} = 25

x^{2} + (y - 3)^{2} = 81

(x - 5)^{2} + y^{2} = 25

What is (x-4)^2+(y-2)^2=4 ?
The solution to (x-4)^2+(y-2)^2=4 is Circle with (a,b)=(4,2),r=2