What is a^2+b^2=1044 ?

The solution to a^2+b^2=1044 is Circle with (a,b)=(0,0),r=sqrt(1044)

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a^2+b^2=1044

a^{2} + b^{2} = 1044

(a, b) = (0, 0), r = 1044

Solution steps

a^{2} + b^{2} = 1044

Rewrite

a^{2} + b^{2} = 1044

in the form of the standard circle equation

(a - 0)^{2} + (b - 0)^{2} = (1044)^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 1044

(x + 3)^{2} + (y - 2)^{2} = 8

2 x^{2} + 2 y^{2} = 5

2 x^{2} + 2 y^{2} = 9

(x + 4)^{2} + y^{2} = 9

x^{2} + y^{2} + 4 x + 2 y + 1 = 0

What is a^2+b^2=1044 ?
The solution to a^2+b^2=1044 is Circle with (a,b)=(0,0),r=sqrt(1044)