What is 3x^2+18x+3y^2=0 ?

The solution to 3x^2+18x+3y^2=0 is Circle with (a,b)=(-3,0),r=3

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3x^2+18x+3y^2=0

3 x^{2} + 18 x + 3 y^{2} = 0

(a, b) = (- 3, 0), r = 3

Solution steps

3 x^{2} + 18 x + 3 y^{2} = 0

Rewrite

3 x^{2} + 18 x + 3 y^{2} = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 0)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 3, 0), r = 3

x^{2} + y^{2} + 5 x = 0

x^{2} - 6 x + y^{2} + 10 y - 2 = 0

x^{2} + y^{2} + 8 x - 6 y + 9 = 0

(x - 5)^{2} + (y - 2)^{2} = 36

4 x^{2} + 4 y^{2} - 12 x + 16 y - 5 = 0

What is 3x^2+18x+3y^2=0 ?
The solution to 3x^2+18x+3y^2=0 is Circle with (a,b)=(-3,0),r=3