What is (x-3)^2+(y+5)^2=36 ?

The solution to (x-3)^2+(y+5)^2=36 is Circle with (a,b)=(3,-5),r=6

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(x-3)^2+(y+5)^2=36

(x - 3)^{2} + (y + 5)^{2} = 36

(a, b) = (3, - 5), r = 6

Solution steps

(x - 3)^{2} + (y + 5)^{2} = 36

Rewrite

(x - 3)^{2} + (y + 5)^{2} = 36

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 5))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (3, - 5), r = 6

x^{2} + y^{2} + 18 x + 4 y - 15 = 0

x^{2} + y^{2} + 2 x + 14 y - 31 = 0

x^{2} + 4 x + y^{2} - 8 y - 5 = 0

x^{2} + y^{2} + 1 x + 5 y - 56 = 0

\frac{1}{2} x^{2} + \frac{1}{2} y^{2} - \frac{1}{8} = 0

What is (x-3)^2+(y+5)^2=36 ?
The solution to (x-3)^2+(y+5)^2=36 is Circle with (a,b)=(3,-5),r=6