What is (x-2)^2+(y+3)^2=100 ?

The solution to (x-2)^2+(y+3)^2=100 is Circle with (a,b)=(2,-3),r=10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-2)^2+(y+3)^2=100

(x - 2)^{2} + (y + 3)^{2} = 100

(a, b) = (2, - 3), r = 10

Solution steps

(x - 2)^{2} + (y + 3)^{2} = 100

Rewrite

(x - 2)^{2} + (y + 3)^{2} = 100

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 3))^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (2, - 3), r = 10

2 x^{2} + 2 y^{2} + 3 x + 5 y = 5

x^{2} - 12 x + y^{2} + 2 y - 12 = 0

x^{2} + y^{2} - 14 x + 8 y + 40 = 0

x^{2} + y^{2} + 10 x - 8 y + 37 = 0

(x - 5)^{2} + (y + 6)^{2} = 20

What is (x-2)^2+(y+3)^2=100 ?
The solution to (x-2)^2+(y+3)^2=100 is Circle with (a,b)=(2,-3),r=10