What is 2x^2+6x+2y^2-8y= 11/2 ?

The solution to 2x^2+6x+2y^2-8y= 11/2 is Circle with (a,b)=(-3/2 ,2),r=3

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2x^2+6x+2y^2-8y= 11/2

2 x^{2} + 6 x + 2 y^{2} - 8 y = \frac{11}{2}

(a, b) = (- \frac{3}{2}, 2), r = 3

Solution steps

2 x^{2} + 6 x + 2 y^{2} - 8 y = \frac{11}{2}

Rewrite

2 x^{2} + 6 x + 2 y^{2} - 8 y = \frac{11}{2}

in the form of the standard circle equation

(x - (- \frac{3}{2}))^{2} + (y - 2)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- \frac{3}{2}, 2), r = 3

x^{2} + y^{2} - 22 x - 12 y + 150 = 0

x^{2} + y^{2} + 4 x - 6 y + 2 = 0

x^{2} + 8 y + y^{2} + 7 = 0

(x - 1)^{2} + (y - 4)^{2} = 4

x^{2} + 4 x + y^{2} + 8 y + 16 = 0

What is 2x^2+6x+2y^2-8y= 11/2 ?
The solution to 2x^2+6x+2y^2-8y= 11/2 is Circle with (a,b)=(-3/2 ,2),r=3