What is (x-512)^2+y^2=256 ?

The solution to (x-512)^2+y^2=256 is Circle with (a,b)=(512,0),r=16

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(x-512)^2+y^2=256

(x - 512)^{2} + y^{2} = 256

(a, b) = (512, 0), r = 16

Solution steps

(x - 512)^{2} + y^{2} = 256

Rewrite

(x - 512)^{2} + y^{2} = 256

in the form of the standard circle equation

(x - 512)^{2} + (y - 0)^{2} = 1 6^{2}

Therefore the circle properties are:

(a, b) = (512, 0), r = 16

x^{2} + y^{2} - x - 6 y + \frac{1}{4} = 0

x^{2} + y^{2} + 6 x - 8 y + 21 = 0

2 5^{2} = a^{2} + b^{2}

x^{2} + y^{2} - 10 x - 2 y + 10 = 0

x^{2} + y^{2} = 3

What is (x-512)^2+y^2=256 ?
The solution to (x-512)^2+y^2=256 is Circle with (a,b)=(512,0),r=16