What is (x-7)^2+(y-4)^2=25 ?

The solution to (x-7)^2+(y-4)^2=25 is Circle with (a,b)=(7,4),r=5

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(x-7)^2+(y-4)^2=25

(x - 7)^{2} + (y - 4)^{2} = 25

(a, b) = (7, 4), r = 5

Solution steps

(x - 7)^{2} + (y - 4)^{2} = 25

Rewrite

(x - 7)^{2} + (y - 4)^{2} = 25

in the form of the standard circle equation

(x - 7)^{2} + (y - 4)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (7, 4), r = 5

x^{2} + y^{2} + 6 x + 4 y + 9 = 0

x^{2} + y^{2} = 4

x^{2} + y^{2} + 16 x - 14 y = 316

x^{2} + 2 x + y^{2} = 55 + 10 y

x^{2} + y^{2} = 5

What is (x-7)^2+(y-4)^2=25 ?
The solution to (x-7)^2+(y-4)^2=25 is Circle with (a,b)=(7,4),r=5