What is x^2+5x+y^2=0 ?

The solution to x^2+5x+y^2=0 is Circle with (a,b)=(-5/2 ,0),r= 5/2

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x^2+5x+y^2=0

x^{2} + 5 x + y^{2} = 0

(a, b) = (- \frac{5}{2}, 0), r = \frac{5}{2}

Solution steps

x^{2} + 5 x + y^{2} = 0

Rewrite

x^{2} + 5 x + y^{2} = 0

in the form of the standard circle equation

(x - (- \frac{5}{2}))^{2} + (y - 0)^{2} = (\frac{5}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{5}{2}, 0), r = \frac{5}{2}

x^{2} + y^{2} - 6 x - 8 y - 26 = 0

(x + 2)^{2} + (y - 8)^{2} = 2

x^{2} + y^{2} + 2 x - 2 y - 23 = 0

6 x^{2} + 6 y^{2} + 12 x + 9 y - 54 = 0

(x + 3)^{2} + (y - 2)^{2} = 81

What is x^2+5x+y^2=0 ?
The solution to x^2+5x+y^2=0 is Circle with (a,b)=(-5/2 ,0),r= 5/2