What is (x-4)^2+(y-1)^2=49 ?

The solution to (x-4)^2+(y-1)^2=49 is Circle with (a,b)=(4,1),r=7

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(x-4)^2+(y-1)^2=49

(x - 4)^{2} + (y - 1)^{2} = 49

(a, b) = (4, 1), r = 7

Solution steps

(x - 4)^{2} + (y - 1)^{2} = 49

Rewrite

(x - 4)^{2} + (y - 1)^{2} = 49

in the form of the standard circle equation

(x - 4)^{2} + (y - 1)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (4, 1), r = 7

x^{2} + y^{2} - 32 x - 8 y + 264 = 0

(x - 2)^{2} + (y + 5)^{2} = 49

\frac{( x + 5 ) ^{2}}{\frac{9}{25}} + \frac{( y + 4 ) ^{2}}{\frac{9}{25}} = 1

x^{2} + y^{2} - 8 x + 14 y + 16 = 0

(x - 0)^{2} + (y - 0)^{2} = 9

What is (x-4)^2+(y-1)^2=49 ?
The solution to (x-4)^2+(y-1)^2=49 is Circle with (a,b)=(4,1),r=7