What is x^2+y^2-10x-24y+25=0 ?

The solution to x^2+y^2-10x-24y+25=0 is Circle with (a,b)=(5,12),r=12

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x^2+y^2-10x-24y+25=0

x^{2} + y^{2} - 10 x - 24 y + 25 = 0

(a, b) = (5, 12), r = 12

Solution steps

x^{2} + y^{2} - 10 x - 24 y + 25 = 0

Rewrite

x^{2} + y^{2} - 10 x - 24 y + 25 = 0

in the form of the standard circle equation

(x - 5)^{2} + (y - 12)^{2} = 1 2^{2}

Therefore the circle properties are:

(a, b) = (5, 12), r = 12

x^{2} - 2 x + 1 + y^{2} - 4 y + 4 = 196

(x - 3)^{2} + (Y (x) - (- 2))^{2} = (\frac{1}{2})^{2}

4 x^{2} + 4 y^{2} - 24 x + 4 y + 9 = 0

x^{2} + y^{2} - 8 x + 4 y + 19 = 0

x^{2} + y^{2} - 14 y - 51 = 0

What is x^2+y^2-10x-24y+25=0 ?
The solution to x^2+y^2-10x-24y+25=0 is Circle with (a,b)=(5,12),r=12