What is 3(x+5)^2+3(y+2)^2=27 ?

The solution to 3(x+5)^2+3(y+2)^2=27 is Circle with (a,b)=(-5,-2),r=3

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3(x+5)^2+3(y+2)^2=27

3 (x + 5)^{2} + 3 (y + 2)^{2} = 27

(a, b) = (- 5, - 2), r = 3

Solution steps

3 (x + 5)^{2} + 3 (y + 2)^{2} = 27

Rewrite

3 (x + 5)^{2} + 3 (y + 2)^{2} = 27

in the form of the standard circle equation

(x - (- 5))^{2} + (y - (- 2))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 5, - 2), r = 3

1 - x^{2} = y^{2}

3 x^{2} + 3 (y + 1)^{2} = \frac{1}{3}

x^{2} + (y + 1)^{2} = 25

\frac{x ^{2} + y ^{2} - 2 x + y - 3}{2} \geq 0

x^{2} + (y + 1)^{2} = 16

What is 3(x+5)^2+3(y+2)^2=27 ?
The solution to 3(x+5)^2+3(y+2)^2=27 is Circle with (a,b)=(-5,-2),r=3